Rmo 1993 Solutions 2021 -

Given the scope, I'll present the clean solution to the correct known problem:

Better: Set EA = m, EB = xm; FA = n, FC = yn. Then AB/AC = (xm+m)/(yn+n) = m(x+1)/n(y+1). But DB/CD = m(x+1)/n(y+1). But also from Menelaus: x * (n/(yn)) * (CD/DB) =1 ⇒ x * (1/y) * (CD/DB)=1 ⇒ CD/DB = y/x.

But known result: only n=1, 3? Check n=3: 10 divides 7? No. So maybe only n=1? Then trivial. rmo 1993 solutions

For ( n \leq 4 ), test directly:

But DB/CD = AB/AC (angle bisector theorem). Given the scope, I'll present the clean solution

The reflect a golden era of Indian olympiad training—problems that are deep yet accessible. Key takeaways for modern aspirants:

Thus the actual known inequality from RMO 1993 had a different constant. Without the exact original, we stop here. But also from Menelaus: x * (n/(yn)) *

The RMO exam is conducted for students in grades 8-12. The exam consists of a single paper with 6-8 problems, which are designed to test mathematical skills, problem-solving abilities, and logical reasoning. The syllabus for the RMO exam is not explicitly defined, but it is generally based on the school curriculum for mathematics up to grade 12.