Rs Aggarwal Class 12 Solutions Differentiation Pdf

Take log: ( \log u = \cos x \cdot \log x ). Differentiate w.r.t ( x ): ( \frac1u \fracdudx = -\sin x \cdot \log x + \frac\cos xx ) Thus, ( \fracdudx = x^\cos x \left[ -\sin x \log x + \frac\cos xx \right] )

The PDF repeatedly emphasizes: ( \fracddx(u/v) = \fracv u' - u v'v^2 ) (minus sign in numerator). rs aggarwal class 12 solutions differentiation pdf

Do not read the PDF like a novel. Differentiation is a skill , not a spectator sport . Take log: ( \log u = \cos x \cdot \log x )

The official solved PDF for this chapter typically includes: rs aggarwal class 12 solutions differentiation pdf